document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325664>Question 325664</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having some trouble solving this problem because I forgot how to set it up. I just need the first two steps and I can figure it out from there. I need to solve it using a logarithmic equation: 3^(2x+7)=3^(1/2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233157 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3^(2x+7)=3^(1/2)<BR>\n" );
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document.write( "Take the log(base 3) of both sides to get:<BR>\n" );
document.write( "2x+7 = 1/2<BR>\n" );
document.write( "Then solve for \"x\".<BR>\n" );
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document.write( "Note: log(base a) of a^x = x<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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