document.write( "Question 325632: The product of two positive consecutive integers is 41 more than their sum. Find the integers. \r
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document.write( "(I have gotten this far, but do not know how to show the next step.)\r
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document.write( "first integer = x
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document.write( "second integer = x+1
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document.write( "+ 41 more their sum =
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document.write( "x(x+1) = 41 + x + x + 1
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document.write( "x^2 + x = 42 + 2x
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document.write( "x^2 + x - (2x) = 42 + 2x - (2x)
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document.write( "x^2 - x = 42
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document.write( "x^2 - x - (42) = 42 - (42)
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document.write( "x^2 - x - 42 = 0
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document.write( "= ??????\r
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Algebra.Com's Answer #233147 by JBarnum(2146)![]() ![]() You can put this solution on YOUR website! find 2 numbers that multiply to get 42 and add to get -1 \n" ); document.write( "-7 and +6 -7*6=-42 -7+6=-1 \n" ); document.write( "(x-7)(x+6)=0 \n" ); document.write( "x=7,-6 \n" ); document.write( "since x has to be possitive \n" ); document.write( "then the numbers have to be 7,8 \n" ); document.write( " |