document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325634>Question 325634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. 2 angles are supplementary. 1 angle is 5 more than 3 times the other. find the angles??<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233144 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233144\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this problem, you are going to have to write two equations using what you know. <BR>\n" );
document.write( "First, you know that you have two supplementary angles.  This means that together the angles add up to 180 degrees. So:<BR>\n" );
document.write( "A + B = 180 (where A = measure of angle one, B = measure of angle two)<BR>\n" );
document.write( "Second, you now that angle one is 5 more than 3 times angle two:<BR>\n" );
document.write( "A = 5 + 3B<BR>\n" );
document.write( "Now you can plug in the second equation into the first and solve for B:<BR>\n" );
document.write( "A + B = 180<BR>\n" );
document.write( "(5 + 3B) + B = 180<BR>\n" );
document.write( "5 + 4B = 180<BR>\n" );
document.write( "4B = 175<BR>\n" );
document.write( "B = 43.75<BR>\n" );
document.write( "Finally, plug this value into the first equation to find A:<BR>\n" );
document.write( "A + B = 180<BR>\n" );
document.write( "A + 43.75 = 180<BR>\n" );
document.write( "A = 136.25<BR>\n" );
document.write( "So angle A is 136.25 degrees and angle B is 43.75 degrees. </SPAN>\n" );
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