document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325620>Question 325620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The path of a ball projected in the air can be represented  by the equation h=-16t^2+64t where h represents height, and t represents time. At what times is the ball 48 feet high?\r<BR>\n" );
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document.write( "a.)-1 second and -3 seconds<BR>\n" );
document.write( "b.)1 second and 3 seconds<BR>\n" );
document.write( "c.)1 second and 4 sesconds<BR>\n" );
document.write( "d.)1 second and 2 seconds </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233135 by </B><A HREF=/tutors/aboutme.mpl?userid=juicystarr17><B>juicystarr17(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=juicystarr17><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At height 48 feet, -16t^2 + 64t = 48<BR>\n" );
document.write( "=> 16t^2 - 64t + 48 = 0<BR>\n" );
document.write( "=> t^2 - 4t + 3 = 0<BR>\n" );
document.write( "=> t^2 - t - 3t + 3 = 0<BR>\n" );
document.write( "=> t(t - 1) - 3(t - 1) = 0<BR>\n" );
document.write( "=> (t - 3)(t - 1) = 0<BR>\n" );
document.write( "=> t = 3, 1<BR>\n" );
document.write( "Hence, the ball is at a height of 48 feet at time 1 sec and 3 sec.<BR>\n" );
document.write( "Answer: b <BR>\n" );
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