document.write( "Question 325599: A and B starts running towards each other with speed of 30 m/hr and 20 miles/hr initially they are 500 miles apart when they start.After how many hr will they meet. \n" ); document.write( "
Algebra.Com's Answer #233122 by mananth(16946) You can put this solution on YOUR website! speed of A = 30 m/hr \n" ); document.write( "speed of B = 20 m/hr. \n" ); document.write( ".. \n" ); document.write( "Let them meet at distance x miles from A \n" ); document.write( "so B runs 500-x \n" ); document.write( "Time is the same. \n" ); document.write( ".. \n" ); document.write( "Time = Distance / speed \n" ); document.write( "x/30= (500-x) /20 \n" ); document.write( "20x=30(500-x) \n" ); document.write( "20x=15000-30x \n" ); document.write( "50x = 15000 \n" ); document.write( "x= 300. they will meet 300 miles from where A started. \n" ); document.write( "speed of A = 30 mph \n" ); document.write( "time = 300 / 30 \n" ); document.write( "= 10 hours. \n" ); document.write( "They will meet after 10 hours \n" ); document.write( " |