document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325582>Question 325582</A>: <I><SPAN STYLE=\"word-break: break-all;\">  PROVE THAT sinA/1+cosA + 1+cosA/sinA=2cosecA </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233109 by </B><A HREF=/tutors/aboutme.mpl?userid=AAfter+Search><B>AAfter Search(61)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AAfter+Search><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To prove, sinA/1+cosA + 1+cosA/sinA=2cosecA<BR>\n" );
document.write( "L.H.S. = sinA/1+cosA + 1+cosA/sinA <BR>\n" );
document.write( "= [sin^2A + (1 + cosA)^2]/sinA(1 + cosA) <BR>\n" );
document.write( "= (sin^2A + 1 + cos^2A + 2cosA)/sinA(1 + cosA) <BR>\n" );
document.write( "= (1 + 1 + 2cosA)/sinA(1 + cosA) [since,sin^2A + cos^2A = 1]<BR>\n" );
document.write( "= (2 + 2cosA)/sinA(1 + cosA) <BR>\n" );
document.write( "= 2(1 + cosA)/sinA(1 + cosA) = 2/sinA <BR>\n" );
document.write( "= 2 cosecA [since 1/sinA = cosecA]<BR>\n" );
document.write( "= R.H.S.<BR>\n" );
document.write( "Hence, Proved </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );