document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325534>Question 325534</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Missy made her annual income of RM25,710 in the fourth year and RM38,560 in the ninth year working in SIMEC Ltd. Assuming that her annual income behave like an arithmethic sequence:<BR>\n" );
document.write( "a. How much was her annual income in the first year </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233104 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Missy made her annual income of RM25,710 in the fourth year and RM38,560 in the ninth year working in SIMEC Ltd. Assuming that her annual income behave like an arithmethic sequence:<BR>\n" );
document.write( "a. How much was her annual income in the first year\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Since this is an arithmetic sequence, we can determine the difference between the years by subtracting year 4's amount from year 9's amount, and then divide this amount by 5 (the difference between the years), or,\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2838560+-+25710%29%2F5 ALIGN=MIDDLE  ALT=\"%2838560+-+25710%29%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >  =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12850%2F5 ALIGN=MIDDLE  ALT=\"12850%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" > = $2,570\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Since year 1 to year 4 covers 3 years, we multiply $2,570 by 3 and subtract this result from year 4's amount. This gives us: $25,710 - $7,710 = $18,000.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "This means that her annual income in the first year was: $<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2818000%29 ALIGN=MIDDLE  ALT=\"highlight_green%2818000%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "This first year annual income could have also been found using the arithmetic progression formula, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t%5Bn%5D+=+t%5B1%5D+%2B+%28n+-+1%29d ALIGN=MIDDLE  ALT=\"t%5Bn%5D+=+t%5B1%5D+%2B+%28n+-+1%29d\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t%5Bn%5D ALIGN=MIDDLE  ALT=\"t%5Bn%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the term, \"n\" is the term number, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t%5B1%5D ALIGN=MIDDLE  ALT=\"t%5B1%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the first term, and d is the common difference. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );