document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325506>Question 325506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are lengthened by 3 km, the area becomes 81 square kilometers.Find the length of the original square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233103 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233103\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are lengthened by 3 km, the area becomes 81 square kilometers.Find the length of the original square\r<BR>\n" );
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document.write( "Let one side of original square be S\r<BR>\n" );
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document.write( "Since a side of the new, lengthened square is 3 km greater than one side of the original square, then one side of the new, lengthened square is S + 3\r<BR>\n" );
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document.write( "Since the new, lengthened square has an area of 81 sq. km, then we'll have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28S+%2B+3%29%5E2+=+81 ALIGN=MIDDLE  ALT=\"%28S+%2B+3%29%5E2+=+81\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "(S + 3)(S + 3) = 81\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%5E2+%2B+6S+%2B+9+=+81 ALIGN=MIDDLE  ALT=\"S%5E2+%2B+6S+%2B+9+=+81\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%5E2+%2B+6S+-+72+=+0 ALIGN=MIDDLE  ALT=\"S%5E2+%2B+6S+-+72+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "(S + 12)(S - 6) = 0\r<BR>\n" );
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document.write( "Therefore, S, or one side of original square is either -12, or 6, but since we CANNOT have a negative measurement, we IGNORE S = - 12, which leaves one side of the original square: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%286%29 ALIGN=MIDDLE  ALT=\"highlight_green%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > km. </SPAN>\n" );
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