document.write( "Question 325534: Missy made her annual income of RM25,710 in the fourth year and RM38,560 in the ninth year working in SIMEC Ltd. Assuming that her annual income behave like an arithmethic sequence:
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document.write( "a. How much was her annual income in the first year \n" );
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Algebra.Com's Answer #233089 by info@email-tutors.com(9)![]() ![]() You can put this solution on YOUR website! An arithemetic sequence is an additive one. This means that each year an unknown amount \"x\" is added to each sequence. Between the 4th and 9th years, there are 5 sequences. Also, between the 4th and 9th years, there are 12850 RM. \r \n" ); document.write( "\n" ); document.write( "12850 / 5 = 2570 RM per year. Between the fourth and ninth years, you add 2570 to each year. Between the first and fourth years, you subtract 2570 to each year (you are going backwards, so it requires subtraction instead of division). \r \n" ); document.write( "\n" ); document.write( "therefore, the third year would be 38560 - 2570\r \n" ); document.write( "\n" ); document.write( "the second year would be: 38560 - (2*2570) \n" ); document.write( "The first year would be: 38560 - (3 * 2570) = 30850 RM\r \n" ); document.write( "\n" ); document.write( "That is the answer. We hope that we have been of help. Should you require any additional information, please feel free to contact us via our profile. \r \n" ); document.write( "\n" ); document.write( "Sincerely,\r \n" ); document.write( "\n" ); document.write( "The Email Tutors Team \n" ); document.write( "www.email-tutors.com \n" ); document.write( " |