document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325506>Question 325506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are lengthened by 3 km, the area becomes 81 square kilometers.Find the length of the original square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233078 by </B><A HREF=/tutors/aboutme.mpl?userid=info@email-tutors.com><B>info@email-tutors.com(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=info@email-tutors.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=info@email-tutors.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233078\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of the original square was 6 km. Here is why: \r<BR>\n" );
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document.write( "6+3 = 9\r<BR>\n" );
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document.write( "9 squared = 81\r<BR>\n" );
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document.write( "You can also solve it algebraically. The area of the square is 81. Let \"x\" be the original length. If \"x+3\" is the new length, then \"x+3\" squared would be equal to 81. \"x+3\" squared is x^2 + 6x + 9 = 81\r<BR>\n" );
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document.write( "subtract nine from both sides to get: 72 = x^2 + 6x\r<BR>\n" );
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document.write( "use the quadratic formula, and you will get \"6\" as your solution.  </SPAN>\n" );
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