document.write( "Question 37750: The width of a rectangle is one-fourth the length. The perimeter of the rectangle is one hundred thirty feet. What is the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #23301 by jcmtnez(53)\"\" \"About 
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Perimeter P=130 feet
\n" ); document.write( "Width w=x
\n" ); document.write( "Length l=4x
\n" ); document.write( "Perimeter P=2(w+l)
\n" ); document.write( "Applying the fromula
\n" ); document.write( "P = 2(x+4x)
\n" ); document.write( "P = 2(5x)
\n" ); document.write( "P = 10x
\n" ); document.write( "130 = 10x
\n" ); document.write( "130/10 = x
\n" ); document.write( "13 = x ,therfore the width is 13 feet
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