document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=647>Question 647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would like all work shown please.\r<BR>\n" );
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document.write( "2log(base of 2)1024 = 3x + 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #233 by </B><A HREF=/tutors/aboutme.mpl?userid=janinecb><B>janinecb(25)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=janinecb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start by dividing both sides by 2 to get the log by itself.<BR>\n" );
document.write( "log(base of 2)1024 = 1/2(3x + 1)\r<BR>\n" );
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document.write( "Then you want to think about what log(base of 2)1024 equals. Remember that raising the base of 2 to some exponent equals 1024. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5Ey+=+1024 ALIGN=MIDDLE  ALT=\"2%5Ey+=+1024\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E10+=+1024 ALIGN=MIDDLE  ALT=\"2%5E10+=+1024\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So, log(base of 2)1024 actually equals 10.<BR>\n" );
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document.write( "10 = 1/2(3x + 1) Now multiply both sides by 2.<BR>\n" );
document.write( "20 = 3x + 1 Now subtract 1 from both sides.<BR>\n" );
document.write( "19 = 3x Now divide both sides by 3.<BR>\n" );
document.write( "19/3 = x </SPAN>\n" );
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