document.write( "Question 325361: the present age of a women is three years more that three times the age of her daughter. three years hence, the womans age will be ten years more than twice the age of her daughter. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #232997 by stanbon(75887)\"\" \"About 
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the present age of a women is three years more that three times the age of her daughter.
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\n" ); document.write( "m = 3d
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\n" ); document.write( "\n" ); document.write( "three years hence, the womans age will be ten years more than twice the age of her daughter.
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\n" ); document.write( "(m+3) = 2(d+3)+10
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\n" ); document.write( "\n" ); document.write( "find their present ages.
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\n" ); document.write( "Substitute for \"m\" and solve for \"d\":
\n" ); document.write( "(3d+3) = 2(d+3)+10
\n" ); document.write( "3d+3 = 2d+6+10
\n" ); document.write( "d = 13 (daughter's age NOW)
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\n" ); document.write( "Since m = 3d, m = 39 (mother's age NOW)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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