document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325334>Question 325334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A number consists of two digits.The digit at the ten's place is two times the digit at the unit's place.The number formed by reversing the digits is 27 less than the original number.Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232993 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "let x be in the tens place and y in the units place.<BR>\n" );
document.write( "x=2y<BR>\n" );
document.write( "10y+x=10x+y -27<BR>\n" );
document.write( "9y-9x=-27<BR>\n" );
document.write( "plug the value of x in the equation<BR>\n" );
document.write( "9y-18y=-27<BR>\n" );
document.write( "-9y=-27<BR>\n" );
document.write( "y=3<BR>\n" );
document.write( "x=6\r<BR>\n" );
document.write( "\n" );
document.write( "the number is 63 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );