document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325348>Question 325348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the digits of two-digit number is 13.twice the ones digits is two more than four times the tens digit.find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232988 by </B><A HREF=/tutors/aboutme.mpl?userid=AAfter+Search><B>AAfter Search(61)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AAfter+Search><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be 10x + y<BR>\n" );
document.write( "Given, x + y = 13; y = 13 - x<BR>\n" );
document.write( "2y = 4x + 2; therefore 2(13 - x) = 4x + 2<BR>\n" );
document.write( "26 - 2x = 4x + 2<BR>\n" );
document.write( "=> -6x = -24<BR>\n" );
document.write( "=> x = 4, hence y = 13 - 4 = 9<BR>\n" );
document.write( "Hence, the required two-digit number is 4 X 10 + 9 = 49 </SPAN>\n" );
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