document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325335>Question 325335</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide 300 into two parts so that half of one part may be less than the other by 48 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232984 by </B><A HREF=/tutors/aboutme.mpl?userid=AAfter+Search><B>AAfter Search(61)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AAfter+Search><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232984\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution: Let x + y = 300, where x and y are two (parts)numbers<BR>\n" );
document.write( "Given, x - y/2 = 48<BR>\n" );
document.write( "=> x = 48 + y/2<BR>\n" );
document.write( "Hence, 48 + y/2 + y = 300<BR>\n" );
document.write( "3y/2 = 252<BR>\n" );
document.write( "y = 2 X 252 / 3 = 504 / 3 = 168<BR>\n" );
document.write( "x = 300 - 168 = 132<BR>\n" );
document.write( "Hence, the two parts (numbers)are 132 and 168. </SPAN>\n" );
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