document.write( "Question 325321: I purchased 300 shares; I purchased 3 times as many shares of common as I did preferred. Common shares currently have a par of $40, preferred shares cost 3/4 more. What is the per share price of preferred shares? And How much is my total purchase price of all shares? \n" ); document.write( "
Algebra.Com's Answer #232980 by Theo(13342)\"\" \"About 
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total shares is 300
\n" ); document.write( "x = common
\n" ); document.write( "y = preferred\r
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\n" ); document.write( "\n" ); document.write( "purchased 3 times as many common as preferred so:\r
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\n" ); document.write( "\n" ); document.write( "x = 3*y\r
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\n" ); document.write( "\n" ); document.write( "common have a par of $40.
\n" ); document.write( "preferred cost 3/4 more.\r
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\n" ); document.write( "\n" ); document.write( "preferred must cost 1.75 * common which makes the price of the preferred share equal to 70.\r
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\n" ); document.write( "\n" ); document.write( "40 + 30 = 70\r
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\n" ); document.write( "\n" ); document.write( "preferred is 3/4 more per share than the price of the common.\r
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\n" ); document.write( "\n" ); document.write( "3/4 * 40 = 30.\r
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\n" ); document.write( "\n" ); document.write( "total purchase price would be calculated as follows:\r
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\n" ); document.write( "\n" ); document.write( "x + y = 300
\n" ); document.write( "x = 3*y making this equation:\r
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\n" ); document.write( "\n" ); document.write( "3*y + y = 300 which becomes:
\n" ); document.write( "4*y = 300\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 4 to get:\r
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\n" ); document.write( "\n" ); document.write( "y = 75\r
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\n" ); document.write( "\n" ); document.write( "since x = 3*y, then x = 225.\r
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\n" ); document.write( "\n" ); document.write( "x + y = 300 results in 225 + 75 = 300 which is correct.\r
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\n" ); document.write( "\n" ); document.write( "total purchase price of all shares is 225 * 40 + 75 * 70 = 14250\r
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