document.write( "Question 325338: Alvin's father is seven times as old as him. One year ago, he was nine times as old as Alvin. Find Alvin's present age. \n" ); document.write( "
Algebra.Com's Answer #232976 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let son's age be x \n" ); document.write( "father'e age = 7x \n" ); document.write( ".. \n" ); document.write( "1 year ago their ages were \n" ); document.write( "son x-1 \n" ); document.write( "father 7x-1 \n" ); document.write( ".. \n" ); document.write( "7x-1= 9(x-1) \n" ); document.write( "7x-1=9x-9 \n" ); document.write( "-2x=-8 \n" ); document.write( "x=4 Alvin's age now\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |