document.write( "Question 325338: Alvin's father is seven times as old as him. One year ago, he was nine times as old as Alvin. Find Alvin's present age. \n" ); document.write( "
Algebra.Com's Answer #232976 by mananth(16946)\"\" \"About 
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let son's age be x
\n" ); document.write( "father'e age = 7x
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\n" ); document.write( "1 year ago their ages were
\n" ); document.write( "son x-1
\n" ); document.write( "father 7x-1
\n" ); document.write( "..
\n" ); document.write( "7x-1= 9(x-1)
\n" ); document.write( "7x-1=9x-9
\n" ); document.write( "-2x=-8
\n" ); document.write( "x=4 Alvin's age now\r
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