document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325291>Question 325291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of twice one number and three times a second number is 84 sum of thrice the first number and five times the second is 136.what is the number?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232973 by </B><A HREF=/tutors/aboutme.mpl?userid=vidhyak><B>vidhyak(98)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vidhyak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the 2 numbers be x,y <BR>\n" );
document.write( " the sum of twice one number and three times a second number is 84 <BR>\n" );
document.write( "2x + 3y =84 ......eq 1\r<BR>\n" );
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document.write( "sum of thrice the first number and five times the second is 136<BR>\n" );
document.write( "3x +5y =136 ......eq 2 \r<BR>\n" );
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document.write( "Multiply eq1 by 3 and eq 2 by 2 to cancel out 'x'<BR>\n" );
document.write( "6x + 9y =252<BR>\n" );
document.write( "6x +10y =272 \r<BR>\n" );
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document.write( "Subtract the above equations <BR>\n" );
document.write( "-y = -20<BR>\n" );
document.write( "y = 20\r<BR>\n" );
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document.write( "Substitute y = 20 in eq 1<BR>\n" );
document.write( "2x + 3y =84<BR>\n" );
document.write( "2x + 3(20) =84<BR>\n" );
document.write( "2x + 60 =84<BR>\n" );
document.write( "2x  =84 -60<BR>\n" );
document.write( "2x  = 24<BR>\n" );
document.write( "x =12\r<BR>\n" );
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document.write( "x = 12, y = 20 </SPAN>\n" );
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