document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325289>Question 325289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2.how can i solve this system of equation by substitution -7x-2y=-13,x-2y=11?<BR>\n" );
document.write( "pls help me.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232945 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> from the second statement u can isolate x to get x=11+2y. we will use the right side of this equation to sub into the first equation's x variable.\r<BR>\n" );
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document.write( "-7(11+2y)-2y=-13<BR>\n" );
document.write( "-77-14y-2y = -13<BR>\n" );
document.write( "-16y=64<BR>\n" );
document.write( "y=-4\r<BR>\n" );
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document.write( "use this value into either equation 1 or 2 to get x. using equation 2 will be easier so since we already know x=11+2y, x=11+2(-4), x=11-8, x=3\r<BR>\n" );
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document.write( "check:<BR>\n" );
document.write( "-7(3)-2(-4)=-21+8 = -13, as expected<BR>\n" );
document.write( "and 3-2(-4)=3+8=11, as expected\r<BR>\n" );
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document.write( "therefore x=3, y=-4 </SPAN>\n" );
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