document.write( "Question 325272: Solve the following equation.\r
\n" ); document.write( "\n" ); document.write( "(x+7)/(x^(2)-25)-(1)/(x-5)=x^(2)-4)/(x^(2)-25)
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Algebra.Com's Answer #232934 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2B7%29%2F%28x%5E2-25%29-1%2F%28x-5%29=%28x%5E2-4%29%2F%28x%5E2-25%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( " Factor \"x%5E2-25\" to get \"%28x%2B5%29%28x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B7-1%28x%2B5%29=x%5E2-4\" Multiply every term by the LCD \"%28x%2B5%29%28x-5%29\" to clear out the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B7-x-5=x%5E2-4\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B7-x-5-x%5E2%2B4=0\" Get every term to the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-x%5E2%2B0x%2B6=0\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6=0\" Multiply every term by -1 to make the leading coefficient positive.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"x%5E2-6\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=1\", \"B=0\", and \"C=-6\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%280%29+%2B-+sqrt%28+%280%29%5E2-4%281%29%28-6%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=0\", and \"C=-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+0-4%281%29%28-6%29+%29%29%2F%282%281%29%29\" Square \"0\" to get \"0\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+0--24+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-6%29\" to get \"-24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+0%2B24+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%280--24%29\" as \"sqrt%280%2B24%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+24+%29%29%2F%282%281%29%29\" Add \"0\" to \"24\" to get \"24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+24+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+2%2Asqrt%286%29%29%2F%282%29\" Simplify the square root (note: If you need help with simplifying square roots, check out this solver) \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280%29%2F%282%29+%2B-+%282%2Asqrt%286%29%29%2F%282%29\" Break up the fraction. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+0+%2B-+sqrt%286%29\" Reduce. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+sqrt%286%29\" or \"x+=+-sqrt%286%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+sqrt%286%29\" or \"x+=+-sqrt%286%29\"
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