document.write( "Question 325142: The product of two consecutive positive odd integers is one less than three times their sum. Find the integers.
\n" ); document.write( " can someone show me how to set this up im so confused
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Algebra.Com's Answer #232933 by checkley77(12844)\"\" \"About 
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X & X+2 ARE THE 2 CONSECUTIVE INTEGERS.
\n" ); document.write( "X(X+2)=3(X+X+2)-1
\n" ); document.write( "X^2+2X=3(2X+2)-1
\n" ); document.write( "X^2+2X=6X+6-1
\n" ); document.write( "X^2+2X-6X-5=0
\n" ); document.write( "X^2-4X-5=0
\n" ); document.write( "(X-5)(X+1)=0
\n" ); document.write( "X-5=0
\n" ); document.write( "X=5 ANS.
\n" ); document.write( "5+2=7 ANS.
\n" ); document.write( "X+1=0
\n" ); document.write( "X=-1 ANS.
\n" ); document.write( "-1+2=1 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "5*7=3(5+7)-1
\n" ); document.write( "35=3*12-1
\n" ); document.write( "35=36-1
\n" ); document.write( "35=35
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