document.write( "Question 325215: the speed of train A is 14mph slower than the speed of train B. train A travels 200 miles in the same time it takes train B to travel 270 miles. find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #232908 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "200=(R-14)T \n" ); document.write( "T=200/(R-14) \n" ); document.write( "270=RT \n" ); document.write( "T=270/R \n" ); document.write( "200/(R-14)=270/R \n" ); document.write( "270(R-14)=200R \n" ); document.write( "270R-3,780=200R \n" ); document.write( "270R-200R=3,780 \n" ); document.write( "70R=3.780 \n" ); document.write( "R=3,780/70 \n" ); document.write( "R=54 ANS. FOR TRAIN B. \n" ); document.write( "54-14=40 ANS. FOR TRAIN A. \n" ); document.write( "PROOF: \n" ); document.write( "200=40T \n" ); document.write( "T=200/40 \n" ); document.write( "T=5 HOURS. \n" ); document.write( "5=270/54 \n" ); document.write( "5=5\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |