document.write( "Question 325255: This is the word problem. Thanks!:\r
\n" ); document.write( "\n" ); document.write( "Jane and Tariq took a canoeing trip, traveling 6 mi upsteam against a 2 mi/h current. They then returned to the same point downstream. If their entire trip took 4 h, how fast can they paddle in still water? (Hint: If r is their rate, in mi/h, in still water, their rate upstream is r-2 and their rate dwonstream is r+2)
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Algebra.Com's Answer #232907 by stanbon(75887)\"\" \"About 
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Jane and Tariq took a canoeing trip, traveling 6 mi upsteam against a 2 mi/h current.
\n" ); document.write( "They then returned to the same point downstream.
\n" ); document.write( "If their entire trip took 4 h, how fast can they paddle in still water? (Hint: If r is their rate, in mi/h, in still water, their rate upstream is r-2 and their rate downstream is r+2)\r
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "rate = r-2 mph ; distance = 6 miles ; time = 6/(r-2) hrs.
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "rate = r+2 mph ; distance = 6 miles ; time = 6/(r+2) hrs
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\n" ); document.write( "Equations:
\n" ); document.write( "time + time = 4 hrs
\n" ); document.write( "6/(r-2) + 6/(r+2) = 4 hrs
\n" ); document.write( "---
\n" ); document.write( "6(r+2) + 6(r-2) = 4(r^2-4)
\n" ); document.write( "12r = 4r^2 - 16
\n" ); document.write( "r^2 - 3r - 4 = 0
\n" ); document.write( "(r-4)(r+1) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "r = 4 mph (rate in still water)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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