document.write( "Question 325255: This is the word problem. Thanks!:\r
\n" ); document.write( "\n" ); document.write( "Jane and Tariq took a canoeing trip, traveling 6 mi upsteam against a 2 mi/h current. They then returned to the same point downstream. If their entire trip took 4 h, how fast can they paddle in still water? (Hint: If r is their rate, in mi/h, in still water, their rate upstream is r-2 and their rate dwonstream is r+2)
\n" ); document.write( "

Algebra.Com's Answer #232903 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "T=D/R
\n" ); document.write( "4=6/(R+2)+6(R-2)
\n" ); document.write( "4=[6(R-2)+6(R+2)]/(R+2)(R-2)
\n" ); document.write( "4=(6R-12+6R+12)/(R^2-4)
\n" ); document.write( "4=12R/(R^2-4)
\n" ); document.write( "4(R^2-4)=12R
\n" ); document.write( "4R^2-16-12R=0
\n" ); document.write( "4R^2-12R-16=0
\n" ); document.write( "4(R^2-3R-4)=0
\n" ); document.write( "4(R-4)(R+1)=0
\n" ); document.write( "R-4=0
\n" ); document.write( "R=4 ANS FOR THE RATE OF THE CANOE IN STILL WATER.
\n" ); document.write( "PROOF:
\n" ); document.write( "4=6/(4+2)+6/(4-2)
\n" ); document.write( "4=6/6+6/2
\n" ); document.write( "4=1+3
\n" ); document.write( "4=4
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );