document.write( "Question 325255: This is the word problem. Thanks!:\r
\n" );
document.write( "\n" );
document.write( "Jane and Tariq took a canoeing trip, traveling 6 mi upsteam against a 2 mi/h current. They then returned to the same point downstream. If their entire trip took 4 h, how fast can they paddle in still water? (Hint: If r is their rate, in mi/h, in still water, their rate upstream is r-2 and their rate dwonstream is r+2) \n" );
document.write( "
Algebra.Com's Answer #232903 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "T=D/R \n" ); document.write( "4=6/(R+2)+6(R-2) \n" ); document.write( "4=[6(R-2)+6(R+2)]/(R+2)(R-2) \n" ); document.write( "4=(6R-12+6R+12)/(R^2-4) \n" ); document.write( "4=12R/(R^2-4) \n" ); document.write( "4(R^2-4)=12R \n" ); document.write( "4R^2-16-12R=0 \n" ); document.write( "4R^2-12R-16=0 \n" ); document.write( "4(R^2-3R-4)=0 \n" ); document.write( "4(R-4)(R+1)=0 \n" ); document.write( "R-4=0 \n" ); document.write( "R=4 ANS FOR THE RATE OF THE CANOE IN STILL WATER. \n" ); document.write( "PROOF: \n" ); document.write( "4=6/(4+2)+6/(4-2) \n" ); document.write( "4=6/6+6/2 \n" ); document.write( "4=1+3 \n" ); document.write( "4=4 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |