document.write( "Question 325257: factor by grouping if possible and check
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Algebra.Com's Answer #232896 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that it's supposed to be: \"8a%5E3-2a%5E2-12a%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"8a%5E3-2a%5E2-12a%2B3\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%288a%5E3-2a%5E2%29%2B%28-12a%2B3%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"2a%5E2%284a-1%29%2B%28-12a%2B3%29\" Factor out the GCF \"2a%5E2\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"2a%5E2%284a-1%29-3%284a-1%29\" Factor out the GCF \"-3\" from the second group.\r
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\n" ); document.write( "\n" ); document.write( "\"%282a%5E2-3%29%284a-1%29\" Factor out \"4a-1\"\r
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\n" ); document.write( "\n" ); document.write( "So \"8a%5E3-2a%5E2-12a%2B3=%282a%5E2-3%29%284a-1%29\"
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