document.write( "Question 325222: Simplify by factoring the square root of 1575x^4 (x is to the 4th power). I don't know how to find the largest perfect square factor of a number, especially bigger numbers.\r
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Algebra.Com's Answer #232876 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%281575%2Ax%5E4%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28225%2A7%2Ax%5E4%29\" Factor \"1575\" into \"225%2A7\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28225%2A7%2Ax%5E2%2Ax%5E2%29\" Factor \"x%5E4\" into \"x%5E2%2Ax%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28225%29%2Asqrt%287%29%2Asqrt%28x%5E2%29%2Asqrt%28x%5E2%29\" Break up the square root using the identity \"sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"15%2Asqrt%287%29%2Asqrt%28x%5E2%29%2Asqrt%28x%5E2%29\" Take the square root of \"225\" to get \"15\".\r
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\n" ); document.write( "\n" ); document.write( "\"15%2Asqrt%287%29%2Ax%2Ax\" Take the square root of \"x%5E2\" to get \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"15x%5E2%2Asqrt%287%29\" Rearrange and multiply the terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%281575%2Ax%5E4%29\" simplifies to \"15x%5E2%2Asqrt%287%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%281575%2Ax%5E4%29=15x%5E2%2Asqrt%287%29\" where \"x%3E=0\"
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