document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325169>Question 325169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When 358, 528 and 698 are in turn divided by a certain number, the remainder is 1 in each case. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232853 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x*y + 1 = 698<BR>\n" );
document.write( "x*y = 697<BR>\n" );
document.write( "697 = 17*41 its only factors<BR>\n" );
document.write( "--> 17<BR>\n" );
document.write( " </SPAN>\n" );
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