document.write( "Question 325150: Please help me solve the following:\r
\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 122m. The length is 10m more than twice the width. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #232838 by Theo(13342)\"\" \"About 
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P = perimeter = 122 meters.
\n" ); document.write( "Perimeter = 2 * ( length + width )
\n" ); document.write( "Let:
\n" ); document.write( "length = L
\n" ); document.write( "width = W
\n" ); document.write( "This makes Perimeter = 2 * (L + W)
\n" ); document.write( "Since length = 2 * width, you get:
\n" ); document.write( "length = 2W
\n" ); document.write( "width = W
\n" ); document.write( "This makes Perimeter = 2 * 3W = 6W
\n" ); document.write( "Since P = 122 meters, you get:
\n" ); document.write( "122 meters = 6W
\n" ); document.write( "Divide both sides of the equation by 6 to get:
\n" ); document.write( "W = 20.3333333 which is the same as:
\n" ); document.write( "W = 20 and 1/3 meters.
\n" ); document.write( "Since L = 2W, then:
\n" ); document.write( "L = 40 and 2/3 meters.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since P = 2 * (L + W) then:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P = 2 * (20 + 1/3 + 40 + 2/3) = 2 * 61 = 122 meters.\r
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\n" ); document.write( "\n" ); document.write( "Your answer is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "W = 20 and 1/3 meters.
\n" ); document.write( "P = 40 and 2/3 meters.\r
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