document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325097>Question 325097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 40cm. If the length is 4cm greater than the width, what are the dimensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232806 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let thwe width be x<BR>\n" );
document.write( "the length will be x+4<BR>\n" );
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document.write( "Perimeter = 2*(L+W)<BR>\n" );
document.write( "= 2(x+x+4)<BR>\n" );
document.write( "=2(2x+4)= 40<BR>\n" );
document.write( "4x+8=40<BR>\n" );
document.write( "add-8<BR>\n" );
document.write( "4x+8-8=40-8<BR>\n" );
document.write( "4x=32<BR>\n" );
document.write( "divide by 4<BR>\n" );
document.write( "4x/4=32/4<BR>\n" );
document.write( "x=8 cm the width<BR>\n" );
document.write( "length = x+4 = 12 cm<BR>\n" );
document.write( " </SPAN>\n" );
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