document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=325058>Question 325058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What line is perpendicular to y=3/5x+1 but contains (5,2)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232773 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Slopes of perpendicular lines are negative reciprocals of each other.\r<BR>\n" );
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document.write( "Your given slope is 3/5.  The slope of the equation we want to find is -5/3.\r<BR>\n" );
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document.write( "We use the point-slope formula: y - a = m(x - b), where the given point (5,2) represents the general point (b,a).\r<BR>\n" );
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document.write( "NOTE: I used a and b to represent the given point but you can use any two letters of choice.\r<BR>\n" );
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document.write( "Let m = -5/3\r<BR>\n" );
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document.write( "Let a = 2\r<BR>\n" );
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document.write( "Let b = 5\r<BR>\n" );
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document.write( "y - 2 = (-5/3)(x - 5)\r<BR>\n" );
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document.write( "y - 2 = (-5/3)(x) + (25/3)\r<BR>\n" );
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document.write( "y = (-5/3)(x) + (25/3) + 2\r<BR>\n" );
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document.write( "y = (-5/3)(x) + (31/3)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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