document.write( "Question 325012: I need to factor x^4-3x^3+8x^2-18x+12 \n" ); document.write( "
Algebra.Com's Answer #232731 by stanbon(75887)\"\" \"About 
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factor x^4-3x^3+8x^2-18x+12
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\n" ); document.write( "The coefficenents add up to zero, so x=1 is a root.
\n" ); document.write( "Therefore x-1 is one of the factors.
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\n" ); document.write( "Use synthetic division to find other Real roots:
\n" ); document.write( "1)....1....-3....8....-18....12
\n" ); document.write( ".......1.....-2...6.....-12...|..0
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\n" ); document.write( "\n" ); document.write( "Quotient x^3 -2x^2 + 6x -12\r
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\n" ); document.write( "I graphed it and found a Real zero at x = 2
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\n" ); document.write( "2).........1.....-2...6.....-12
\n" ); document.write( ".............1.....0...6....|..0\r
\n" ); document.write( "\n" ); document.write( "Quotient: x^2 + 6
\n" ); document.write( "Factors (x+isqrt(6))(x-isqrt(6)(x-2)(x-1)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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