document.write( "Question 324938: Solve the equation for x.
\n" ); document.write( "log2(x) + log2(x - 1) = 1\r
\n" ); document.write( "\n" ); document.write( "I am coming up with x = {2, 1} but the application is telling me to \"Check the syntax of your response.\"\r
\n" ); document.write( "\n" ); document.write( "Please help.
\n" ); document.write( "Alberto
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Algebra.Com's Answer #232667 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
I'll assume you meant log base 2:
\n" ); document.write( "\"log%282%2Cx%29+%2B+log%282%2C%28x+-+1%29%29+=+1\"
\n" ); document.write( "\"log%282%2Cx%28x+-+1%29%29+=+1\"
\n" ); document.write( "\"x%28x+-+1%29+=+2%5E1\"
\n" ); document.write( "\"x%5E2+-+x+=+2\"
\n" ); document.write( "\"x%5E2+-+x+-+2+=+0\"
\n" ); document.write( "\"%28x-2%29%28x%2B1%29+=+0\"
\n" ); document.write( "x = {-1, 2}
\n" ); document.write( ".
\n" ); document.write( "But wait, -1 is an extraneous solution toss it out. Leaving you with:
\n" ); document.write( "x = 2
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