document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=324927>Question 324927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 60% of the weight of a 2,200-pound car should be supported by the rear tires, how many pounds should be supported by the rear tires? \r<BR>\n" );
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document.write( "A.120<BR>\n" );
document.write( "B.600<BR>\n" );
document.write( "C.1,200<BR>\n" );
document.write( "D.1,320<BR>\n" );
document.write( "E.1,600\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232663 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this, you want to find 60% of 2,220 because that is the amount that can be supported by the rear tires.<BR>\n" );
document.write( "First, change 60% to a decimal by dividing by 100:<BR>\n" );
document.write( "60% = 60/100 = 0.6<BR>\n" );
document.write( "Now, multiply this decimal by 2,220 to find 60% of 2,220:<BR>\n" );
document.write( "(0.6)*(2220) = 1320<BR>\n" );
document.write( "So 1,320 pounds should be supported by the rear tires, or answer D. </SPAN>\n" );
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