document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=324894>Question 324894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a linear equation whose graph has the indicated slope and passes through the given point.\r<BR>\n" );
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document.write( "slope -2, point (2,1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232614 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the point-slope formula.\r<BR>\n" );
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document.write( "y - a = m(x - b)\r<BR>\n" );
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document.write( "(2,1) = (b,a)\r<BR>\n" );
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document.write( "y - 1 = -2(x - 2)\r<BR>\n" );
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document.write( "y - 1 = -2x + 4\r<BR>\n" );
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document.write( "y = -2x + 4 + 1\r<BR>\n" );
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document.write( "y = -2x + 5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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