document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=324776>Question 324776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A radioactive substance has a half-life of 26 months.  If after 10 months 42 grams remain, approximate the initial amount to the nearest gram. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232595 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A radioactive substance has a half-life of 26 months.<BR>\n" );
document.write( " If after 10 months 42 grams remain, approximate the initial amount to the nearest gram.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The half-life formula: A = Ao*2^(-t/h)<BR>\n" );
document.write( "where:<BR>\n" );
document.write( "A = resulting amt after t<BR>\n" );
document.write( "Ao = initial amt<BR>\n" );
document.write( "t = time<BR>\n" );
document.write( "h = half-life of substance<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Ao*2^(-10/26) = 42<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Ao * .76598 = 42<BR>\n" );
document.write( "Ao = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=42%2F.76598 ALIGN=MIDDLE  ALT=\"42%2F.76598\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Ao = 55 grams </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );