document.write( "Question 37687: I need your help. Can someone please graph this for me?\r
\n" ); document.write( "\n" ); document.write( "Find the vertex and intercepts for each parabola. Sketch the graph.
\n" ); document.write( "g(x) = x^2 + x - 6
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\n" ); document.write( "By completing the square:
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\n" ); document.write( "Vertex = (-0.5,-6.25). y-intercept = -6
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Algebra.Com's Answer #23257 by Alwayscheerful(414)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B1x%2B-6+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A-6=25\".
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\n" ); document.write( " Discriminant d=25 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+25+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%281%29%2Bsqrt%28+25+%29%29%2F2%5C1+=+2\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%281%29-sqrt%28+25+%29%29%2F2%5C1+=+-3\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B1x%2B-6\" can be factored:
\n" ); document.write( " \"1x%5E2%2B1x%2B-6+=+1%28x-2%29%2A%28x--3%29\"
\n" ); document.write( " Again, the answer is: 2, -3.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-6+%29\"

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\n" ); document.write( "\n" ); document.write( "The formula to find the vertex is \"-b%2F2a\". That formula will give you the \"x\" value of the vertex. To find the \"y\" value, plug \"x\" back into the equation. \r
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\n" ); document.write( "\n" ); document.write( "\"-b%2F2a=x\"
\n" ); document.write( "\"-1%2F2%281%29=x\"
\n" ); document.write( "\"-1%2F2=x\"\r
\n" ); document.write( "\n" ); document.write( "Plug back into the original equation\r
\n" ); document.write( "\n" ); document.write( "\"y=1%28-1%2F2%29%5E2%2B1%28-1%2F2%29-6\"
\n" ); document.write( "\"y=1%281%2F4%29%2B%28-1%2F2%29-6\"
\n" ); document.write( "\"y=.25-.5-6\"
\n" ); document.write( "\"y=-.25-6\"
\n" ); document.write( "\"y=-6.25\"\r
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\n" ); document.write( "\n" ); document.write( "To find the y-intercept, you must set \"x\" equal to 0
\n" ); document.write( "\"y=1%280%29%5E2%2B1%280%29-6\"
\n" ); document.write( "\"y=-6\"\r
\n" ); document.write( "\n" ); document.write( "Hope this helps!
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