document.write( "Question 324398: a collection of 130 coins of quarters and dimes.each coin is worth 4 times its face value, collection is worth $94.00 How many of each type of coin? \n" ); document.write( "
Algebra.Com's Answer #232523 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a collection of 130 coins of quarters and dimes. \n" ); document.write( "each coin is worth 4 times its face value, collection is worth $94.00 \n" ); document.write( "How many of each type of coin? \n" ); document.write( ": \n" ); document.write( "Let x = no. of quarters \n" ); document.write( "then, since there are 130 coins, \n" ); document.write( "(130-x) = no. of dimes \n" ); document.write( ": \n" ); document.write( "multiplying the face values by 4, we have: \n" ); document.write( ".4(130-x) + 1.00(x) = 94 \n" ); document.write( "52 - .4x + 1.0x = 94 \n" ); document.write( "x - .4x = 94 - 52 \n" ); document.write( ".6x = 42 \n" ); document.write( "x = \n" ); document.write( "x = 70 quarters \n" ); document.write( "and \n" ); document.write( "130 - 70 = 60 dimes \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution: 4[.10(60) + .25(70)] = $94 \n" ); document.write( " \n" ); document.write( " |