document.write( "Question 324770: how do you work 4logX= 2logX+3 \n" ); document.write( "

Algebra.Com's Answer #232486 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"4log%28%28X%29%29=+2log%28%28X%29%29%2B3\"$
\n" ); document.write( " $\"log%28%28X%5E4%29%29=log%28%28X%5E2%29%29%2B3\"$
\n" ); document.write( " $\"log%28%28X%5E4%29%29-log%28%28X%5E2%29%29=3\"$
\n" ); document.write( " $\"log%28%28X%5E4%29%2F%28X%5E2%29%29=3\"$
\n" ); document.write( " $\"log%28%28X%5E2%29%29=3\"$
\n" ); document.write( " $\"X%5E2=10%5E3=1000\"$
\n" ); document.write( " $\"X=sqrt%281000%29=10sqrt%2810%29\"$ \n" ); document.write( "

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