document.write( "Question 324732: Determine the measure (in degrees) of the third angle in an isosceles triangle, if the third angle is 10 more than one-half of either of the equal measure angles.
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Algebra.Com's Answer #232478 by jessica43(140) $\"\"$ $\"About$

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To solve this problem, you are going to have to write 2 equations using what you know.
\n" ); document.write( "First, you know that this is an isosceles triangle, meaning 2 of the angles are equal and all 3 angles add up to 180 degrees:
\n" ); document.write( "A + B + B = 180 or A + 2B =180 (with B = measure of either of the equal angles of the triangle in degrees, A = measure of the third angle in degrees)
\n" ); document.write( "Second, you know that the third angle (A) is 10 more than one-half of either of the equal measure angles (B):
\n" ); document.write( "A = 10 + (1/2)B
\n" ); document.write( "Now plug in the second equation into the first equation and solve for B:
\n" ); document.write( "A + 2B = 180
\n" ); document.write( "(10 + (1/2)B) + 2B = 180 (now add (1/2)B and 2B)
\n" ); document.write( "10 + (5/2)B = 180 (now subtract 10 from each side)
\n" ); document.write( "(5/2)B = 170 (now divide each side by (5/2), or 2.5 which is the same thing)
\n" ); document.write( "B = 68
\n" ); document.write( "So the measure of each of the equal angles is 68 degrees. Plug in this value to the first equation to find the measure of angle A:
\n" ); document.write( "A + 2B =180
\n" ); document.write( "A + (2*68) = 180
\n" ); document.write( "A + 136 = 180
\n" ); document.write( "A = 44
\n" ); document.write( "So the measure of the third angle in the triangle is 44 degrees.\r
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