document.write( "Question 324746: Flying against the wind, an airplane travels 2280km in 3 hours. Flying with the wind, the same plane travels 6100km in 5 hours. What is the rate of the plane in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #232467 by Fombitz(32388)\"\" \"About 
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Rate*Time=Distance
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\n" ); document.write( "Let P be the rate of the plane in still air.
\n" ); document.write( "Let W be the rate of the wind.
\n" ); document.write( "\"%28P-W%293=2280\"
\n" ); document.write( "1.\"P-W=760\"
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\n" ); document.write( "\"%28P%2BW%295=6100\"
\n" ); document.write( "2.\"P%2BW=1220\"
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\n" ); document.write( "Add eq. 1 and eq. 2 to eliminate W.
\n" ); document.write( "\"2P=1980\"
\n" ); document.write( "\"highlight%28P=990%29\"kph
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"990-W=760\"
\n" ); document.write( "\"highlight%28W=230%29\"kph
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