document.write( "Question 37643: Need help! I have to turn in this assignment by tonight and I'm having problems with this.\r
\n" ); document.write( "\n" ); document.write( "1) Solve the following equations.
\n" ); document.write( "a) sqrt(x) - 2=1
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\n" ); document.write( "\n" ); document.write( "b)sqrt(x)^3 = 27
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\n" ); document.write( "\n" ); document.write( "c)3^sqrt(x)^2 = 9
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Algebra.Com's Answer #23242 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
a) sqrt(x) - 2=1
\n" ); document.write( "sqrt(x)=3
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "x=9\r
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\n" ); document.write( "\n" ); document.write( "b)sqrt(x)^3 = 27
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "x^3=27^2
\n" ); document.write( "Take the cube root of both sides to get:
\n" ); document.write( "x=(27^2)^(1/3)=[27^(1/3]^2
\n" ); document.write( "x=3^2=9
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\n" ); document.write( "\n" ); document.write( "c)3^sqrt(x)^2 = 9
\n" ); document.write( "3^(sqrt(x)^2)= 3^2
\n" ); document.write( "sqrt(x)^2=2
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "x^2=4
\n" ); document.write( "x=2
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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