document.write( "Question 37643: Need help! I have to turn in this assignment by tonight and I'm having problems with this.\r
\n" ); document.write( "\n" ); document.write( "1) Solve the following equations.
\n" ); document.write( "a) sqrt(x) - 2=1
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\n" ); document.write( "\n" ); document.write( "b)sqrt(x)^3 = 27
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\n" ); document.write( "\n" ); document.write( "c)3^sqrt(x)^2 = 9
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Algebra.Com's Answer #23240 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
1. \"+sqrt%28x%29+-+2+=+1+\"
\n" ); document.write( "\"+sqrt%28x%29+=+3+\"
\n" ); document.write( "now square both sides:
\n" ); document.write( "x = 9\r
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\n" ); document.write( "\n" ); document.write( "2. \"+sqrt%28x%5E3%29+=+27+\"
\n" ); document.write( "well you would square both sides then take the cube root of both sides. Alternatively since \"raising to a power\" and \"rooting\" are opposite processes, it doesn't actually matter the order we do this, so i shall find the cube root first:\r
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\n" ); document.write( "\n" ); document.write( "\"+sqrt%28x%29+=+root%283%2C+27%29+\"
\n" ); document.write( "\"+sqrt%28x%29+=+3+\"
\n" ); document.write( "--> x = 9\r
\n" ); document.write( "\n" ); document.write( "3. \"+3%5E%28sqrt%28x%29%5E2%29+=+9+\"
\n" ); document.write( "or... \"+3%5E%28sqrt%28x%29%5E2%29+=+3%5E2+\"
\n" ); document.write( "so by \"symmetry\" of this, we can say that \"+sqrt%28x%5E2%29+=+2+\"
\n" ); document.write( "and also, \"sqrt%28x%5E2%29+\" is just x anyway, so
\n" ); document.write( "x = 2\r
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\n" ); document.write( "\n" ); document.write( "jon.
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