document.write( "Question 37643: Need help! I have to turn in this assignment by tonight and I'm having problems with this.\r
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document.write( "1) Solve the following equations.
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document.write( "a) sqrt(x) - 2=1
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document.write( "b)sqrt(x)^3 = 27
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document.write( "c)3^sqrt(x)^2 = 9
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Algebra.Com's Answer #23240 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! 1. \n" ); document.write( " \n" ); document.write( "now square both sides: \n" ); document.write( "x = 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. \n" ); document.write( "well you would square both sides then take the cube root of both sides. Alternatively since \"raising to a power\" and \"rooting\" are opposite processes, it doesn't actually matter the order we do this, so i shall find the cube root first:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--> x = 9\r \n" ); document.write( "\n" ); document.write( "3. \n" ); document.write( "or... \n" ); document.write( "so by \"symmetry\" of this, we can say that \n" ); document.write( "and also, \n" ); document.write( "x = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " |