document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=324648>Question 324648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Agnew drew a circle which had an area of 113 square yards. Which is closest to the circumference of Agnew’s circle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232387 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the radius.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area+=+pi%2Ar%5E2+=+113 ALIGN=MIDDLE  ALT=\"Area+=+pi%2Ar%5E2+=+113\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+sqrt%28113%2Fpi%29 ALIGN=MIDDLE  ALT=\"r+=+sqrt%28113%2Fpi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "C = 2*pi*r<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C+=+2pi%2Asqrt%28113%2Fpi%29 ALIGN=MIDDLE  ALT=\"C+=+2pi%2Asqrt%28113%2Fpi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "C =~ 37.683 yds<BR>\n" );
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