document.write( "Question 324606: find the two digitd numbers which has the square of sum is equal to the obtained number by reversing its digits \n" ); document.write( "
Algebra.Com's Answer #232362 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
[xy]=n
\n" ); document.write( "\"%28x%2By%29%5E2=10y%2Bx\"
\n" ); document.write( "x and y cant = 0 but can be 1-9
\n" ); document.write( "x+y=2^2=4 nope has only 1 digit
\n" ); document.write( "x+y=3^2=6 nope has only 1 digit
\n" ); document.write( "x+y=4^2=16: y=1 x=6 x+y=7 nope the sum doesnt equal the original sum
\n" ); document.write( "x+y=5^2=25: y=2 x=5 x+y=7 nope the sum doesnt equal the original sum
\n" ); document.write( "x+y=6^2=36: y=3 x=6 x+y=9 nope the sum doesnt equal the original sum
\n" ); document.write( "x+y=7^2=49: y=4 x=9 x+y=13 nope the sum doesnt equal the original sum
\n" ); document.write( "x+y=8^2=64: y=6 x=4 x+y=10 nope the sum doesnt equal the original sum
\n" ); document.write( "x+y=9^2=81: y=8 x=1 x+y=9 yes!!!
\n" ); document.write( "x+y=10^2=100 nope has 3 digits\r
\n" ); document.write( "\n" ); document.write( "by process of elimination
\n" ); document.write( "x=1 y=8
\n" ); document.write( "check to make sure:
\n" ); document.write( "\"%28x%2By%29%5E2=10y%2Bx\"
\n" ); document.write( "\"%281%2B8%29%5E2=10%288%29%2B1\"
\n" ); document.write( "\"9%5E2=81\"
\n" ); document.write( "\"81=81\"
\n" ); document.write( "correct
\n" ); document.write( "
\n" );