document.write( "Question 323414: Probability: find the indicated probabilities. Using the following information. Show your work.
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document.write( "In a sample bag of M&M's candy there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange.\r
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document.write( "What is the probability of getting 1 green M&M if only one is taken at a time?\r
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document.write( "What is the probability of getting 3 yellow M&M's if 3 are taken at a time?\r
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document.write( "What is the probability of getting 1 brown and 2 orange M&M's if 3 are taken at a time? \n" );
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Algebra.Com's Answer #232327 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! 5 Brown \n" ); document.write( "6 Yellow \n" ); document.write( "4 Blue \n" ); document.write( "3 Green \n" ); document.write( "2 Orange \n" ); document.write( "20 Total \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "P(1 Green)=3/20 \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "P(1st Yellow)=6/20 \n" ); document.write( "P(2nd Yellow)=5/19 \n" ); document.write( "P(3rd Yellow)=4/18 \n" ); document.write( "P(Y,Y,Y)=(6/20)(5/19)(4/18)=1/57 \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "P(1st Brown)=5/20 \n" ); document.write( "P(2nd Orange)=2/19 \n" ); document.write( "P(3rd Orange)=1/18 \n" ); document.write( "P(B,O,O)=(5/20)(2/19)(1/18)=1/684 \n" ); document.write( " |