document.write( "Question 37638: -5(d+3)=7d+5 and 2/5(a+10)=1/4(a+20), these should help me with the rest of the problems. I am doing the problems so that I can check his work. Thanks. \n" ); document.write( "
Algebra.Com's Answer #23232 by josmiceli(19441)\"\" \"About 
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-5(d+3)=7d+5 and 2/5(a+10)=1/4(a+20)
\n" ); document.write( "use the distributive law
\n" ); document.write( "-5d -15 = 7d + 5
\n" ); document.write( "add 5d to both sides
\n" ); document.write( "0 -15 = 12d + 5
\n" ); document.write( "subtract 5 from both sides
\n" ); document.write( "12d = -20
\n" ); document.write( "d = -5/3
\n" ); document.write( "check
\n" ); document.write( "-5(-5/3 + 9/3) = 7(-5/3) + 15/3
\n" ); document.write( "25/3 - 45/3 = -35/3 + 15/3
\n" ); document.write( "-20/3 = -20/3
\n" ); document.write( "OK
\n" ); document.write( "-----------------------------
\n" ); document.write( "2/5(a+10)=1/4(a+20)
\n" ); document.write( "(2/5)a + 4 = (1/4)a + 5
\n" ); document.write( "(2/5)a - (1/4)a = 1
\n" ); document.write( "find LCD
\n" ); document.write( "(8/20)a - (5/20)a = 1
\n" ); document.write( "multiply both sides by 20
\n" ); document.write( "8a - 5a = 20
\n" ); document.write( "3a = 20
\n" ); document.write( "a = 20/3
\n" ); document.write( "check
\n" ); document.write( "(2/5)(20/3 + 10) = (5/20)(20/3 + 20)
\n" ); document.write( "(2/5)(20/3 + 30/3) = (5/20)(20/3 + 60/3)
\n" ); document.write( "(2/5)(50/3) = (5/20)(80/3)
\n" ); document.write( "100/15 = 400/60
\n" ); document.write( "20/3 = 20/3
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "
\n" );