document.write( "Question 324573: I am trying to complete the square. Here's what I did:\r
\n" ); document.write( "\n" ); document.write( "x(2x+3)-1=0
\n" ); document.write( "x=2x+3+1=0+1
\n" ); document.write( "x=2x+4=1
\n" ); document.write( "x= (2,-2)
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Algebra.Com's Answer #232315 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I am trying to complete the square.
\n" ); document.write( "x(2x+3)-1=0
\n" ); document.write( "---
\n" ); document.write( "2x^2 + 3x - 1 = 0
\n" ); document.write( "2(x^2 + (3/2)x) = 1
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\n" ); document.write( "Complete the square:
\n" ); document.write( "2(x^2 + (3/2)x + (3/4)^2) = 1 + 2(3/4)^2
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\n" ); document.write( "2(x+(3/4))^2 = 1+9/8
\n" ); document.write( "---
\n" ); document.write( "2(x+(3/4))^2 = 17/8
\n" ); document.write( "---
\n" ); document.write( "(x+(3/4))^2 = 17/16
\n" ); document.write( "---
\n" ); document.write( "x+(3/4) = sqrt(17)/4 or x+(3/4) = -sqrt(17)/4
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\n" ); document.write( "x = (-3+sqrt(17))/4 or x = (-3-sqrt(17))/4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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