document.write( "Question 324560: The diagonal of a rectangle is twenty-five inches more than its width. The length of the rectangle is twenty-three inches more than its width. What is the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #232288 by stanbon(75887)\"\" \"About 
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The diagonal of a rectangle is twenty-five inches more than its width. The length of the rectangle is twenty-three inches more than its width. What is the width of the rectangle?
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\n" ); document.write( "diag = width + 25
\n" ); document.write( "length = width + 23
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\n" ); document.write( "diag^2 = width^2 + length^2
\n" ); document.write( "(w+25)^2 = w^2 + (w+23)^2
\n" ); document.write( "w^2 +50w + 625 = w^2 + w^2 + 46w + 529
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\n" ); document.write( "w^2-4w-96 = 0
\n" ); document.write( "(w+8)(w-12) = 0
\n" ); document.write( "w = 12 inches (width)
\n" ); document.write( "diag = w + 25 = 37 inches
\n" ); document.write( "length = w + 23 = 35 inches
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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