document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=324556>Question 324556</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Multiplying rational expression. I just need to know if this is right and if not the right way to do it.\r<BR>\n" );
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document.write( "3÷a²+a•2a+2÷6 = 3÷a(a+1)• 2(a+1)÷2•3  =a </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #232285 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=232285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  I just need to know if this is right and if not the right way to do it. <BR>\n" );
document.write( "[3÷(a²+a)]•[(2a+2)÷6]<BR>\n" );
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document.write( "= [3÷(a(a+1))• [(2(a+1))÷(2•3)]<BR>\n" );
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document.write( "Cancel factors that are common to <BR>\n" );
document.write( "a numerator and a denominator, such<BR>\n" );
document.write( "as 3,2, and (a+1), to get:<BR>\n" );
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document.write( "= 1/a<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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